Output of program

public class Test { public static int y; public static void foo(int x) { System.out.print("foo "); y = x; } public static int bar(int z) { System.out.print("bar "); return y = z; } public static void main(String [] args ) { int t = 0; assert t > 0 : bar(7); assert t > 1 : foo(8); /* Line 18 */ System.out.println("done "); } }

A. bar B. bar done C. foo done D. Compilation fails Answer: Option D Explanation: The foo() method returns void. It is a perfectly acceptable method, but because it returns void it cannot be used in an assert statement, so line 18 will not compile. Learn more problems on : Assertions Discuss about this problem : Discuss in Forum http://www.indiabix.com/online-test/java-programming-test/61